15m^+11m^2+2m=0

Solution for 15m^+11m^2+2m=0 equation:

15m^+11m^2+2m=0

We add all the numbers together, and all the variables

11m^2+17m=0

a = 11; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·11·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*11}=\frac{-34}{22}
=-1+6/11
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*11}=\frac{0}{22}
=0
$